Using Coulomb's Law, calculate the force of repulsion between a positive
charge of 110 Coulombs and another positive charge of 220 coulombs
separated by a distance of 2 meters. Use scientific notation.
(Hint: use the proportionality constant)
F=k•q1•q2/r²
k =9•10^9 N•m²/C²
To calculate the force of repulsion between two positive charges using Coulomb's Law, you need to use the following formula:
F = k * (q1 * q2) / r^2
where F is the force of repulsion, k is the proportionality constant, q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
The proportionality constant, k, is given by:
k = 9 * 10^9 N * m^2 / C^2
Given that q1 = 110 C, q2 = 220 C, and r = 2 m, we can substitute these values into the formula.
First, let's convert k to scientific notation:
k = 9 * 10^9 N * m^2 / C^2
Next, plug in the values into the formula:
F = (9 * 10^9 N * m^2 / C^2) * (110 C * 220 C) / (2 m)^2
Simplifying the formula:
F = (9 * 10^9 N * m^2 / C^2) * (24200 C^2) / 4 m^2
F = (9 * 24200) * (10^9 N * m^2 / C^2) / 4 m^2
F = 217800 * (10^9 N * m^2) / (4 m^2 * C^2)
F = 217800 * (10^9 / 4) N / C^2
F = 545500 * (10^9 / 10^2) N / C^2
F = 545500 * (10^7) N / C^2
Finally, expressing the result in scientific notation:
F = 5.455 * 10^12 N / C^2
Therefore, the force of repulsion between the two charges is 5.455 * 10^12 Newtons per Coulomb squared.