Find three consecutive even integers whose sum is 252
Start by dividing 252 by 3.
Can you take it from there?
84
Let's represent the three consecutive even integers as x, x+2, and x+4.
According to the problem, the sum of the three consecutive even integers is 252. So, we can write the equation:
x + (x + 2) + (x + 4) = 252
Simplifying the equation, we get:
3x + 6 = 252
Subtracting 6 from both sides of the equation:
3x = 246
Next, we divide both sides of the equation by 3 to solve for x:
x = 82
Now, we can find the consecutive even integers by substituting the value of x back into our equation:
The three consecutive even integers are 82, 84, and 86.
To find three consecutive even integers whose sum is 252, we can set up an equation as follows:
Let's assume the first even integer is x. Then, the next two consecutive even integers will be x + 2 and x + 4.
The sum of these three integers is x + (x + 2) + (x + 4), which gives us:
3x + 6 = 252
Now, we can solve this equation to find the value of x.
3x = 252 - 6
3x = 246
Dividing both sides by 3:
x = 82
Therefore, the first even integer is 82. The next two consecutive even integers are 82 + 2 = 84 and 82 + 4 = 86.
So, the three consecutive even integers whose sum is 252 are 82, 84, and 86.