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How many gallons of 5% acid solution should be mixed with 20 galllons of a 10% acid solution to obtain an 8% acid solution

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  1. let the amount of the 5% solution that must be added be x gallons
    .05x + .10(20) = .08(20+x)
    times 100
    5x + 10(20) = 8(20+x)
    5x + 200 = 160 + 8x
    -3x = -40
    x = 40/3

    they should add 13 1/3 gallons of the 5% solution.

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