Log² x + log² 3 = 1
log23x = 1
3x = 21 = 2
x = 2/3
To solve the equation log² x + log² 3 = 1 for x, we need to apply logarithmic properties.
First, let's simplify the equation using the property that the sum of logarithms is equal to the logarithm of the product:
log² x + log² 3 = log² (x * 3) = 1
Next, we can rewrite the equation using exponential form:
x * 3 = 2^1
Simplifying further:
x * 3 = 2
Now, divide both sides of the equation by 3 to isolate x:
x = 2/3
Therefore, the solution to the equation log² x + log² 3 = 1 is x = 2/3.