Solve x = log3 15
huh? there's nothing to solve. Just evaluate log3 15.
Now, you probably don't have a log-base-3 key on your calculator, so you have to use what you do have: ln
x = ln15/ln3
How does that work? By definition,
3^log3 15 = 15
ln(3^log3 15) = ln15
now, ln(3^p) = p*ln3, so we have
log3 15 * ln3 = ln15
log3 15 = ln15/ln3
Given that x=log3^5 and y=log3^2, rewrite log3^60 in terms of x and y.
logx(9x^2)[log3(x)]^2=4 i got the x=1/9 and x=3 is that correct?
express log9 in terms of log3 x and log3 y and solve for x and y simultaneously
log3 (2x – 1) – log3 (x – 4) = 2
evaluate log3 27
1) Solve for x in terms of k: log3(x) + log3(x+7) = k; 3 is the base 2) e^(x+5) = e^(x) + 6, solve for x. Please help, I have no idea how to do these and I've tried several times!
solve for x log4 64+ log2 2 ________________ =x log3 81
(2*log7 16)/(log3(√10+1)+log3(√10-1)log7 2
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