# physics

A 3.3-kg ball of clay with a speed of 14 m/s is thrown against a wall and sticks to the wall. What is the magnitude of the impulse exerted on the ball?

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1. It is the product of those two numbers: the momentum change.

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2. initial momentum= mass x velocity
= 3.3 x 14
= 46.2 Ns (to the wall)
final velocity= 0 therfore final momentum = 0

change in momentum = final momentum- initial momentum
= 0 - 46.2 (to the wall)
= 46.2 (away from the wall)
Impulse= change in momentum
= 46.2 Ns (away from the wall)

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