A 3.3-kg ball of clay with a speed of 14 m/s is thrown against a wall and sticks to the wall. What is the magnitude of the impulse exerted on the ball?
It is the product of those two numbers: the momentum change.
initial momentum= mass x velocity
= 3.3 x 14
= 46.2 Ns (to the wall)
final velocity= 0 therfore final momentum = 0
change in momentum = final momentum- initial momentum
= 0 - 46.2 (to the wall)
= 46.2 (away from the wall)
Impulse= change in momentum
= 46.2 Ns (away from the wall)
To find the magnitude of the impulse exerted on the ball, we need to use the principle of conservation of linear momentum. The linear momentum of an object is equal to the product of its mass and velocity.
The formula for impulse is given by:
Impulse = change in momentum
Since the ball sticks to the wall after the collision, its final velocity becomes zero. Therefore, the change in momentum of the ball is equal to the initial momentum of the ball, which can be calculated as follows:
Initial momentum of the ball = mass of the ball × initial velocity of the ball
Substituting the given values into the equation:
Initial momentum of the ball = 3.3 kg × 14 m/s = 46.2 kg·m/s
The magnitude of the impulse exerted on the ball is equal to the magnitude of the change in momentum, which is 46.2 kg·m/s.