The volume of a gas is 250 mL at 340.0 kPa pressure. With the temperature remaining constant, what will the volume be when the pressure is reduced to 50.0 kPa? Don't forget the units.

P1V1 = P2V2

To find the final volume of the gas when the pressure is reduced, we can use the relationship known as Boyle's Law. Boyle's Law states that at constant temperature, the pressure and volume of a gas are inversely proportional.

Mathematically, Boyle's Law can be expressed as:

P₁V₁ = P₂V₂

Where:
- P₁ and V₁ are the initial pressure and volume of the gas
- P₂ and V₂ are the final pressure and volume of the gas

In this case, the initial volume (V₁) is given as 250 mL, the initial pressure (P₁) is 340.0 kPa, and the final pressure (P₂) is 50.0 kPa.

Let's plug these values into the equation and solve for V₂:

P₁V₁ = P₂V₂

(340.0 kPa)(250 mL) = (50.0 kPa)(V₂)

Now we can solve for V₂:

85000 kPa⋅mL = 50.0 kPa⋅V₂
85000 kPa⋅mL / 50.0 kPa = V₂

1700 mL = V₂

Therefore, the final volume of the gas when the pressure is reduced to 50.0 kPa will be 1700 mL.