if a solution contains 255mL of ethanol and 375 mL ofwater, what is the percent of ethanol in the soution
40.5%
Assuming the the volumes are additive (they aren't) we have a total of 255 + 375 = 630 mL.
%v/v = (255/630)*100 = ?
To determine the percent of ethanol in the solution, we need to know the total volume of the solution. However, the total volume is not provided in the question.
To calculate the percentage of ethanol, we can use the formula:
% Ethanol = (Volume of ethanol / Total volume of solution) × 100
Let's assume the total volume of the solution is 255 mL + 375 mL = 630 mL.
Now we can calculate the percent of ethanol in the solution:
% Ethanol = (255 mL / 630 mL) × 100
% Ethanol = 0.4048 × 100
% Ethanol = 40.48%
Therefore, the solution contains approximately 40.48% ethanol.
To find the percent of ethanol in the solution, you need to calculate the ethanol's volume as a percentage of the total solution's volume. Here's how you can do it:
1. Determine the total volume of the solution by adding the volumes of ethanol and water:
Total volume = volume of ethanol + volume of water
Total volume = 255 mL + 375 mL
Total volume = 630 mL
2. Calculate the percentage of ethanol by dividing the volume of ethanol by the total volume and then multiplying by 100:
Percent of ethanol = (volume of ethanol / total volume) x 100
Percent of ethanol = (255 mL / 630 mL) x 100
Percent of ethanol ≈ 40.48%
Therefore, the solution contains approximately 40.48% ethanol.