When you add 100ml of a 0.1M HCl solution to 200 ml of 0.4M NaOH solution what is the pH?
can you please show detailed work. o don't understand this
you have 10 millimoles of acid, 80 millimoles of base per liter, or net 70millimoles of base per liter.
p(OH)=-log(10E-3)=3
pH=14-pOH=11