Identify the unknown particles X and X' in the following nuclear reactions. (In parts (a) and (b), enter only the missing product or reactant.) A) X + 4over2 HE -> 24over12 Mg+1over0 n B) 235over92U+1over0 n -> 90over38Sr+X+2and 1over0 n
1) 21 over 10 Ne - Neon
2)144 over 54 Xe - Xenon
You have not written any reaction with an X' term.
For the missing particle, the total mass (superscripts, left) must be the same on both sides of the arrow. The total charge (subscripts, right) must also be the same.
21X10 + 4He2 -> 24Mg12 + 1n0
The 21X10 particle is 21Ne10, which is Neon-10, a stable isotope.
Your second reaction (B) is a nuclear fission process. I do not understand why you wrote "2and" on the right side. It makes no sense. There are probably 2 neutrons (1n0) among
the fission products. One such process is
235H92 + 1n0 -> 94Sr38 + 140Xe54 + 2 1n0
There are other fission fragment possibilities. Yours has strontium-90 as a fission fragment
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To identify the unknown particles in the given nuclear reactions, we need to balance the reactions and use the principles of conservation of mass number (protons + neutrons) and conservation of charge.
Let's analyze each reaction separately:
A) X + 4over2 HE -> 24over12 Mg + 1over0 n
In this reaction, we have an unknown particle X reacting with 4over2 helium, resulting in the formation of 24over12 magnesium and an unknown particle. To identify the unknown particles, we need to balance the mass numbers and atomic numbers on both sides of the equation.
Since helium has a mass number of 4 and an atomic number of 2, we can determine that the unknown particle X has a mass number of 24 - 4 = 20 and an atomic number of 12 - 2 = 10. Therefore, the unknown particle X in this reaction is 20over10 Ne (Neon). The product is 24over12 Mg (Magnesium) and 1over0 n (neutron).
B) 235over92U + 1over0 n -> 90over38Sr + X + 2and 1over0 n
In this reaction, we have an unknown particle X produced along with other products. Again, we need to balance the mass numbers and atomic numbers on both sides of the equation to determine the unknown particle.
Uranium-235 (235over92U) reacts with a neutron (1over0 n), resulting in the formation of 90over38Sr (Strontium-90), an unknown particle (X), and two neutrons. To identify the unknown particle, we subtract the mass numbers and atomic numbers of the known particles from the product side.
The mass number of the unknown particle X is 235 - 90 = 145, and the atomic number is 92 - 38 = 54. Therefore, the unknown particle X in this reaction is 145over54Xe (Xenon).
To summarize:
A) X + 4over2 HE -> 24over12 Mg + 1over0 n
- Unknown particle X: 20over10 Ne (Neon)
B) 235over92U + 1over0 n -> 90over38Sr + X + 2and 1over0 n
- Unknown particle X: 145over54Xe (Xenon)