In a hypermarket promotional drive, the customers would only have to
pay half of the original price on their second buy of the same item and
one quarter of the original price on their third buy of the same item for
some selected items. A customer bought 3 units of a selected item and
he paid RM280 for the 3 items. What was the original price of 1 unit of
the item?
Let X be the single unit price.
X + 0.5X + 0.25X = 280
1.75 X = 280
X = 160 Renminbi
To find the original price of one unit of the item, we can work backwards using the information provided.
Let's denote the original price of one unit of the item as "x".
According to the promotional drive, the customer would pay half of the original price on their second buy, which means the price would be (1/2)x.
On the third buy, the customer would pay one quarter of the original price, which means the price would be (1/4)x.
According to the information, the customer bought 3 units of the item and paid RM280 for all three items. Therefore, the total cost of the 3 units is RM280.
We can set up an equation to represent this information:
x + (1/2)x + (1/4)x = RM280
To solve this equation, we need to combine like terms:
(1 + 1/2 + 1/4)x = RM280
Now, we can simplify the equation:
(7/4)x = RM280
To isolate x, we need to divide both sides of the equation by (7/4):
x = RM280 * (4/7)
x = RM160
Therefore, the original price of 1 unit of the item was RM160.