14) There are 6 marbles in a bag, 3 blue, 2 red, 1 green. Aubrey reaches into the bag and pulls out a marble, does not replace it, then chooses another. What is the probability that Aubrey chides a blue and then a green marble?
The word "chides" makes no sense here.
(3/6)*(1/5) = 1/10
Sorry meant to type chooses
To find the probability of drawing a blue marble and then a green marble, we need to consider the total number of possible outcomes and the number of favorable outcomes.
Total Number of Possible Outcomes:
There are 6 marbles in the bag initially, so when Aubrey chooses the first marble, there are 6 possible outcomes.
Number of Favorable Outcomes:
Aubrey wants to choose a blue marble first, and there are 3 blue marbles in the bag. So the probability of choosing a blue marble is 3/6 (since there are 6 marbles in total).
After Aubrey selects a blue marble and does not replace it, there are now 5 marbles in the bag. Out of these 5 marbles, there is only 1 green marble. So the probability of choosing a green marble after choosing a blue marble is 1/5.
To find the overall probability, we can multiply the probabilities of each event happening:
Probability of choosing a blue marble and then a green marble:
(3/6) * (1/5) = 3/30 = 1/10
Therefore, the probability that Aubrey chooses a blue marble and then a green marble is 1/10.