The equation of a parabola is
y=(x-5)^2-4. Is the point (5,-6) on this parabola?
Y = (x-5)^2 - 4. (5,-6).
Y = (5-5)^2 - 4 = -4.
When x = s, y = -4 instead of -5.
Therefore, the given point is not on the parabola.
Correction: When x = 5, y = -4 instead of -6.
To determine if the point (5,-6) is on the given parabola, we need to substitute the x and y coordinates of the point into the equation of the parabola and check if it satisfies the equation.
The equation of the parabola is y = (x-5)^2 - 4.
Let's substitute x = 5 and y = -6 into the equation:
-6 = (5-5)^2 - 4
-6 = 0^2 - 4
-6 = 0 - 4
-6 = -4
Since -6 is not equal to -4, the point (5,-6) does not satisfy the equation. Therefore, the point (5,-6) is not on the given parabola.