Intro to probability

A certain pizza restaurant offers three different sizes of pizza and eight different toppings.
How many distinct pizzas having two different toppings can be made?
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I think part of the answer to the question is
(8)\
(2)/ where I choose 2 toppings from 8.

==> 8!/ (6!* 2!)= 28

But im not sure what to do from there, if it's correct.

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asked by Amelie
  1. ok so far.

    Wouldn't those 28 ways also be available in each of the 3 sizes of pizza?

    so final number of ways = 3x28 = 84

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    posted by Reiny
  2. oh, now wasn't that simple, thank you reiny

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    posted by Amelie
  3. Thank you

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    posted by Jason

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