math: bobby has $14 more than tina while seda has twice as much money as bobby. together they have $208. how much money does each have?

T + T + 14 + 2(T + 14) = 208

4T + 42 = 208

4T = 166

T = 41.50

Tina: 41.50
Bobby: 55.50
Seda: 111.00

Bobby = x+14

Tina = x
Seda = 2(x+14)

x+14+x+2x +28 = 208
4x + 42= 208
4x + 42-42= 208 -42
4x = 166
4x/4 = 166/4
x = 41.50
Tina = $ 41.50
Bobby =$ 55.50
Seda = $ 111

j costs twice as much as b. b costs twice as much as k. all three letters together cost 17.50. what is the price of each letter?

To find out how much money each person has, let's break down the information given and solve the problem step by step.

Let's assume Tina has x dollars.

According to the information provided, Bobby has $14 more than Tina, so Bobby would have (x + $14) dollars.

Additionally, Seda has twice as much money as Bobby, so Seda would have 2 * (x + $14) dollars.

Together, the three people have a total of $208, so we can set up the equation:

x + (x + $14) + 2 * (x + $14) = $208

Now let's solve this equation to find the value of x (which represents the amount of money Tina has):

3x + $42 = $208

Subtracting $42 from both sides of the equation:

3x = $208 - $42

3x = $166

Next, divide both sides of the equation by 3:

x = $166 / 3

Calculating this gives us x ≈ $55.33.

So, Tina has approximately $55.33.

To find the amounts for Bobby and Seda:

Bobby has (x + $14) ≈ $55.33 + $14 ≈ $69.33.

Seda has 2 * (x + $14) ≈ 2 * ($69.33) ≈ $138.67.

Therefore, Bobby has approximately $69.33, and Seda has approximately $138.67.