By using the data in this question, estimate how much oxygen a person requires on average in a life time and how far a motor can go using the same amount of oxygen. the typical daily food requirement of a person can be considered to be 1.2 kg of carbohydrate. The person obtains energy by the oxidation of the carbohydrate, which can be represented by the formula (CH2O)n.
a) Construct an equation for the complete combustion of the carbohydrate formula (CH2O)n.
b)The empirical relative formula mass of the carbohydrate is 30. Use your equation above to calculate the number of moles of oxygen required by the person each day.
a)(CH2O)n + nO2 -> nCO2 + nH2O
a) The equation for the complete combustion of the carbohydrate formula (CH2O)n can be represented as:
(CH2O)n + O2 → CO2 + H2O
This equation shows that when the carbohydrate is burned or oxidized completely, it produces carbon dioxide (CO2) and water (H2O).
b) To calculate the number of moles of oxygen required by the person each day, we need to consider the ratio of oxygen to carbohydrate molecules in the combustion reaction.
The empirical formula of the carbohydrate is (CH2O)n and the molecular mass of each carbohydrate molecule is 30 g/mol (given in the question).
From the combustion equation, we see that 1 molecule of carbohydrate requires 1 molecule of oxygen. Therefore, the molar ratio of oxygen to carbohydrate is 1:1.
Now, let's calculate the number of moles of carbohydrate (CH2O)n in 1.2 kg (1200 g) of carbohydrate:
Molar mass of (CH2O)n = 30 g/mol
Number of moles = Mass / Molar mass
= 1200 g / 30 g/mol
= 40 mol
Since the molar ratio of oxygen to carbohydrate is 1:1, the number of moles of oxygen required by the person each day will also be 40 mol.
Please note that this calculation is an estimation, and actual oxygen requirements may vary depending on individual factors such as activity level and metabolism.