if a membrane filter from a cigarette weighs 0.0313g bfore sample has been drawn through and 0.0548g after what is the weight of particluate matter on filter in g and mg/cigarette ?

Volume of air sucked through=32x50ml=?mL=?L
concentration of particulate matter=?mg/L =? mg/m3 please?

I will be happy to check your calcuations. It seems straightforward.

weight of particluate on filter 0.0235g = 23mg/cigarette

volume of air sucked through 32x50ml=
1600ml =1.6 l
I cant figure how to do this
concentration of particulate matter=
?mg/l = ? mg/m3
help appreciated

To find the weight of particulate matter on the filter:

1. Calculate the weight of particulate matter on the filter by subtracting the initial weight of the filter from the weight of the filter after the sample has been drawn through:
Weight of particulate matter on filter = Weight after - Weight before
Weight of particulate matter on filter = 0.0548g - 0.0313g
Weight of particulate matter on filter = 0.0235g

To find the weight of particulate matter per cigarette:

2. Determine the volume of air sucked through the filter:
Volume of air sucked through = 32 x 50 ml
Volume of air sucked through = 1600 ml

3. Convert the volume to liters:
Volume of air sucked through = 1600 ml ÷ 1000 ml/L
Volume of air sucked through = 1.6 L

4. Calculate the concentration of particulate matter in mg/L:
Concentration of particulate matter = Weight of particulate matter on filter / Volume of air sucked through
Concentration of particulate matter = 0.0235g / 1.6 L
Concentration of particulate matter = 0.014688 mg/L

To find the concentration of particulate matter in mg/m³:

5. Assume an air density (ρ) to convert the concentration in mg/L to mg/m³. A common assumption is 1.225 kg/m³.
Convert air density to g/m³: 1.225 kg/m³ × 1000 g/kg = 1225 g/m³

6. Use the formula to convert the concentration in mg/L to mg/m³:
Concentration in mg/m³ = (Concentration in mg/L) × (1000 L/m³) × (Air density in g/m³)
Concentration in mg/m³ = 0.014688 mg/L × 1000 L/m³ × 1225 g/m³
Concentration in mg/m³ ≈ 18.03 mg/m³

So, the weight of particulate matter on the filter is 0.0235g, or 23.5 mg/cigarette. The concentration of particulate matter is approximately 0.014688 mg/L, or 18.03 mg/m³.