Q1=
An 85 cu.meter room.
- How much energy required to heat room temperature from 5C to 22C.
- How long in minutes
Q2=
- a 40 Liter radiator in the same room above. energy input is 5400 watts. In order to increase room temperature from 5C to 22C, how long 5400 Watts will be supplied to radiator and what water temperature is required in radiator to maintain 22C in the room?
Thank you
Q1: It depends upon the heater power level. You should have been provided that infomation.
Q2 depends upon heat loss rate out of the room. I don't know how to answer this with the information provided.
This may help, but it looks rather complicated:
http://www.engineeringtoolbox.com/heat-emission-radiators-d_272.html
Q1:
To calculate the amount of energy required to heat a room, you can use the following formula:
Energy = (mass of air) x (specific heat capacity of air) x (change in temperature)
First, let's calculate the mass of the air in the room. The density of air is approximately 1.2 kg/m^3. So, to find the mass, we multiply the volume of the room (85 cubic meters) by the density:
Mass of air = Volume x Density = 85 m^3 x 1.2 kg/m^3 = 102 kg
The specific heat capacity of air is approximately 1.005 kJ/kg°C. Now, we have the mass and specific heat capacity, so we can calculate the energy required to heat the room:
Energy = 102 kg x 1.005 kJ/kg°C x (22°C - 5°C) = 17,907 kJ
To convert kJ to watts, we divide by the amount of time it takes to heat the room. Since we want to find out how long it takes in minutes, we need to divide the energy by the heating rate.
Let's assume a heating rate of 1000 watts (this can vary depending on the heating system). So, the time required to heat the room is:
Time = Energy / Heating rate = 17,907 kJ / 1000 watts = 17.907 minutes
Therefore, it would take approximately 17.907 minutes to heat the room from 5°C to 22°C.
Q2:
To calculate the time required for a radiator to increase the room temperature from 5°C to 22°C, we need to consider the energy input and the heating rate. Given that the energy input is 5400 watts, we can use the same formula as in Q1:
Energy = (mass of air) x (specific heat capacity of air) x (change in temperature)
However, in this case, we need to solve for time. Rearranging the formula, we have:
Time = Energy / (heating rate)
Given that the energy input is 5400 watts and the heating rate is also 5400 watts:
Time = 5400 watts / 5400 watts = 1 hour
So, the required time to supply 5400 watts to the radiator in order to increase the room temperature from 5°C to 22°C is 1 hour.
To maintain a room temperature of 22°C, the water temperature in the radiator needs to be set accordingly. This can vary depending on the efficiency of the radiator and the heating system. You can consult the manufacturer's specifications or a professional for more precise information regarding the water temperature required in the radiator to maintain the desired room temperature.