a 333 hz and 337 hz tuning forks are struck simultaneously. whats will be the beat frequency?
337-333 = 4 Hz
To determine the beat frequency produced by the simultaneous striking of two tuning forks, we need to find the difference between their frequencies. In this case, the tuning forks have frequencies of 333 Hz and 337 Hz.
The beat frequency (fbeat) can be calculated using the formula:
fbeat = |f1 - f2|
Where f1 and f2 are the frequencies of the two tuning forks.
In this case, substituting the values, we have:
fbeat = |333 Hz - 337 Hz|
Performing the subtraction, we get:
fbeat = |-4 Hz|
Since the absolute value of -4 Hz is 4 Hz, the beat frequency will be 4 Hz.