Express the concentration of a 2.0 M NaOH solution as a mass/volume percent.

Can you please explain how to get the answer?

2M NaOH is 2*40 = 80 g/L soln. That is 8g/100 mL which is 8% m/v.

thanks

Well, first of all, let's "concentrate" on the task at hand. To determine the mass/volume percent, you need to know the mass of NaOH in a given volume of solution.

So, let's assume we have 100 mL of this 2.0 M NaOH solution. In order to find the mass of NaOH, we must use its molar mass. The molar mass of NaOH is approximately 40 g/mol (23 g/mol for sodium + 16 g/mol for oxygen + 1 g/mol for hydrogen).

Now, to calculate the mass of NaOH in 100 mL (0.1 L) of solution, we need to use the formula:

Mass of NaOH = Molarity × Molar Mass × Volume

Mass of NaOH = 2.0 mol/L × 40 g/mol × 0.1 L

So, the mass of NaOH in 100 mL of the solution is 8.0 g.

To express this as a mass/volume percent, we divide the mass of NaOH by the volume of the solution (100 mL) and multiply by 100:

% mass/volume = (mass of NAOH / volume of solution) × 100

% mass/volume = (8.0 g / 100 mL) × 100

And voila! The concentration of the 2.0 M NaOH solution expressed as a mass/volume percent is 8.0%.

To calculate the mass/volume percent of a solution, you need to find the mass of the solute (NaOH) in a given volume of the solution.

Step 1: Find the mass of NaOH in 1 liter (1000 mL) of the 2.0 M NaOH solution.
Since the molar concentration (Molarity) is given as 2.0 M, it means that there are 2 moles of NaOH in 1 liter of solution. The molar mass of NaOH is approximately 40 g/mol (sodium = 23 g/mol, oxygen = 16 g/mol, hydrogen = 1 g/mol).
So, the mass of NaOH in 1 liter of solution is: 2.0 M × 40 g/mol = 80 grams of NaOH.

Step 2: Convert the mass of NaOH in 1 liter to the mass in 100 mL (0.1 L) of the solution.
Since we want to express the concentration as a mass/volume percentage, we need to find the mass of NaOH in 0.1 L (100 mL) of the solution.
Since the mass is directly proportional to the volume, we can use the following formula:
Mass1/Volume1 = Mass2/Volume2.
Rearranging the formula, we get: Mass2 = (Mass1 × Volume2) / Volume1.
Substituting the values, we get: Mass2 = (80 g × 0.1 L) / 1 L = 8 g.

Step 3: Calculate the mass/volume percent.
The mass/volume percent is calculated using the formula: (mass of solute / volume of solution) × 100.
Plugging in the values, we get: (8 g / 100 mL) × 100 = 8%.

Therefore, the concentration of the 2.0 M NaOH solution is 8% mass/volume.

To express the concentration of a solution as a mass/volume percent, you need to determine the mass of the solute (NaOH) in a given volume of the solution.

The first step is to calculate the mass of NaOH in the solution. The formula for calculating the mass of a solute is:

Mass = Concentration × Volume

Given that the concentration of the NaOH solution is 2.0 M (mol/L) and you want to find the mass/volume percent, you need to convert the concentration to grams per liter (g/L) by considering the molar mass of NaOH.

The molar mass of NaOH can be calculated by adding the atomic masses of one sodium atom (Na), one oxygen atom (O), and one hydrogen atom (H), which are 22.99 g/mol, 16.00 g/mol, and 1.01 g/mol, respectively:

Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol

Now, convert the concentration of 2.0 M NaOH to g/L:

Concentration in g/L = Concentration in M × Molar mass NaOH
= 2.0 mol/L × 40.00 g/mol
= 80.00 g/L

Now that we have the mass of NaOH in 1 liter of solution, we can express it as a mass/volume percent.

Mass/volume percent = (Mass of solute / Volume of solution) × 100

For a 2.0 M NaOH solution, the volume of solution is not given. However, if we assume a volume of 1 liter, we can calculate the mass/volume percent:

Mass/volume percent = (80.00 g / 1000 mL) × 100
= 8.00%

Therefore, the concentration of the 2.0 M NaOH solution can be expressed as an 8.00% mass/volume percent if we assume a volume of 1 liter.