Write the ratios for sin A and cos A.
{picture is of a right triangle, ABC.
segment AC is 8, segment AB is 17, and segment
CB is 15.}
sin A=15/17, cos A=8/17
sin A=15/8, cos A=8/17
sin A=15/17, cos A=8/15
sin A=8/17, cos A=15/17
sinA = BC/AB = 15 /17.
cosA = AC/AB = 8 / 17.
To find the ratios for sin A and cos A, we need to use the sides of the right triangle ABC.
In this case, side AB is the hypotenuse, side AC is the adjacent side to angle A, and side CB is the opposite side to angle A.
Using the definitions of sin and cos:
sin A = opposite/hypotenuse
cos A = adjacent/hypotenuse
So, let's substitute the values from the given triangle:
sin A = CB/AB = 15/17
cos A = AC/AB = 8/17
Therefore, the correct ratios are:
sin A = 15/17
cos A = 8/17