Volume of HCl, mL:26.5mL
Volume of NaOH,mL:29.1mL
Molarity of NaOH, mol/L:0.1m/L
balanced equation: NaOh+HCl-->NaCl+H2O
Using the above equation calculate the number of moles of acid required to react with 2.91 moles of base.
Please help me I have no idea what to do.
Just use the definition. What is molarity? It is M = moles/L.
So plug in L and M and you can calculate mols. Or you can rearrange the M = mols/L to M x L = mols. Just apply what you know and this stuff won't get the best of you. Have fun.
Look, why don't you guys just come out with the answer and then explain how you got it instead of leaving it up for the other person to figure it out.
To solve this problem, you can use the balanced equation and the given information to determine the number of moles of acid required to react with 2.91 moles of base.
The balanced equation shows that 1 mole of NaOH reacts with 1 mole of HCl. Therefore, to find the number of moles of acid required, we need to determine the mole ratio between NaOH and HCl.
The given molarity of NaOH (0.1 mol/L) can be used to convert the volume of NaOH (29.1 mL) to moles. The formula to convert volume to moles is:
moles = volume (in liters) x molarity
Converting the volume of NaOH to liters:
29.1 mL = 29.1 mL/1000 mL/L = 0.0291 L
Calculating the number of moles of NaOH:
moles of NaOH = 0.0291 L x 0.1 mol/L = 0.00291 mol
According to the balanced equation, the mole ratio between NaOH and HCl is 1:1. Therefore, 0.00291 moles of NaOH will react with 0.00291 moles of HCl.
Since you want to determine the number of moles of acid required to react with 2.91 moles of base, divide 2.91 by the mole ratio:
number of moles of HCl = 2.91 moles / 1 = 2.91 moles
Therefore, 2.91 moles of HCl is required to react with 2.91 moles of NaOH.