what mass of acetylene, C2H2, will be produced from the reaction of 90 g of calcium carbide, CaC2, with water in the following reaction?
CaC2+2H2O-->C2H2+Ca(OH)2
What mass of acetylene, C2H2
, will be produced from the reaction of 0.900 moles of calcium carbide,
CaC2
, with water in the following reaction?
___CaC2 + ___H2O → ___C2H2 + ___Ca(OH)2
To determine the mass of acetylene (C2H2) produced, we need to first calculate the molar mass of calcium carbide (CaC2) and then use the balanced equation to determine the molar ratio between calcium carbide and acetylene.
1. Calculate the molar mass of CaC2:
- The molar mass of Ca = 40.08 g/mol
- The molar mass of C = 12.01 g/mol
- Since there are two carbon atoms, multiply the molar mass of C by 2
- The molar mass of CaC2 is 40.08 g/mol + (12.01 g/mol × 2) = 64.10 g/mol
2. Use the balanced equation to determine the molar ratio between CaC2 and C2H2:
- From the balanced equation, we can see that 1 mole of CaC2 reacts to produce 1 mole of C2H2.
3. Calculate the number of moles of CaC2:
- Divide the given mass of CaC2 (90 g) by its molar mass (64.10 g/mol) to get the number of moles:
Number of moles = 90 g / 64.10 g/mol = 1.40 moles
4. Determine the number of moles of C2H2 produced:
- Since the molar ratio between CaC2 and C2H2 is 1:1, the number of moles of C2H2 will also be 1.40 moles.
5. Calculate the mass of C2H2 produced:
- Multiply the number of moles of C2H2 (1.40 moles) by its molar mass (26.04 g/mol):
Mass of C2H2 = 1.40 moles × 26.04 g/mol = 36.5 g
Therefore, the mass of acetylene (C2H2) produced from the reaction is approximately 36.5 grams.
To find the mass of acetylene produced, we need to determine the limiting reactant in the reaction. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product formed.
Let's start by calculating the number of moles of calcium carbide (CaC2) using its molar mass. The molar mass of CaC2 is the sum of the atomic masses of calcium (Ca) and carbon (C2).
The atomic mass of Ca is 40.08 g/mol, and the atomic mass of C is 12.01 g/mol. Therefore, the molar mass of CaC2 is:
40.08 g/mol (Ca) + 2 * 12.01 g/mol (C) = 64.10 g/mol.
Next, we can convert the mass of calcium carbide to moles by dividing it by the molar mass:
90 g CaC2 / 64.10 g/mol = 1.40 mol CaC2.
According to the balanced equation, the stoichiometric ratio between CaC2 and C2H2 is 1:1. This means that for every 1 mole of CaC2, 1 mole of C2H2 is produced.
Since the stoichiometric ratio is 1:1, the number of moles of acetylene (C2H2) produced will also be 1.40 mol.
Finally, we can convert the moles of C2H2 to grams using its molar mass. The molar mass of C2H2 is the sum of the atomic masses of carbon (C) and hydrogen (H2).
The atomic mass of C is 12.01 g/mol, and the atomic mass of H is 1.01 g/mol. Therefore, the molar mass of C2H2 is:
2 * 12.01 g/mol (C) + 2 * 1.01 g/mol (H) = 26.04 g/mol.
Now we can calculate the mass of acetylene:
1.40 mol C2H2 * 26.04 g/mol = 36.46 g C2H2.
Therefore, the mass of acetylene produced in the reaction is approximately 36.46 grams.