A student is asked to answer 7 out of 11 questions on an exam.

In how many ways can she select the questions to be answered?

11 choose 7 = 11!/(7!4!)

To find out the number of ways the student can select the questions to be answered, we can use the concept of combinations.

In this case, the student is asked to answer 7 out of 11 questions. So, we need to calculate the number of ways to choose 7 questions from a total of 11 questions.

The formula to calculate the number of combinations is given by nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items to be chosen.

Using this formula, we can substitute n = 11 (total number of questions) and r = 7 (number of questions to be answered).

Therefore, the number of ways the student can select the questions to be answered is:

11C7 = 11! / (7!(11-7)!)
= 11! / (7!4!)
= (11 * 10 * 9 * 8 * 7!) / (7! * 4 * 3 * 2 * 1)
= (11 * 10 * 9 * 8) / (4 * 3 * 2 * 1)
= 330

Therefore, the student can select the questions to be answered in 330 different ways.