The equation of line A is y = –9x + 8. Write an equation that represents a line that is perpendicular to line A.
Y = -9x + 8.
m1 = -9.
m2 = 1/9.
Eq: Y = (1/9)x + 8.
To write an equation that represents a line perpendicular to line A, we need to determine the slope of line A. The given equation of line A is in the form y = mx + b, where m represents the slope.
Comparing the equation y = –9x + 8 to the standard form y = mx + b, we can see that the slope of line A is -9.
To find the slope of a line perpendicular to line A, we need to use the fact that perpendicular lines have slopes that are negative reciprocals of each other. The negative reciprocal of -9 can be found by taking the reciprocal of -9 and then negating the result.
The reciprocal of -9 is -1/9. Negating this value gives 1/9, which is the slope we will use for the line perpendicular to line A.
Now that we have the slope for the perpendicular line, we can proceed to write its equation. Since we don't have any other information about the perpendicular line (such as a point it passes through), we can only express it in slope-intercept form as y = mx + b, where m represents the slope and b represents the y-intercept.
Using the perpendicular slope of 1/9, our equation for the line perpendicular to line A is: y = (1/9)x + b.