If y blue marbles are removed and 30 orange marbles are added to the bag , the probability of getting a green marble become 1/4.Find the value y.
Y can be anything, depending what was originally in the bag.
If there were originally 1 blue and 10 green marbles in the bag, y=1.
If there were originally 101 blue and 10 green marbles in the bag, y=101.
If there were originally 20 blue and 15 green marbles in the bag, y=5.
To find the value of y, we need to use the information provided and set up an equation based on probabilities.
Let's start by understanding the initial situation before any marbles are removed or added. Let's say there are x blue marbles, y green marbles, and z orange marbles in the bag.
Now, according to the problem, y blue marbles are removed. After this removal, we are left with x - y blue marbles, y green marbles, and z orange marbles in the bag.
Next, 30 orange marbles are added to the bag. So, the total number of orange marbles becomes z + 30.
Now, we can set up the equation based on the given information: the probability of getting a green marble becomes 1/4.
The probability of drawing a green marble is given by the fraction of green marbles divided by the total number of marbles: y / (x - y + y + z + 30).
According to the problem, this probability is 1/4. So, we have the equation:
y / (x + z + 30) = 1/4
To find the value of y, we need to solve this equation. Let's simplify it:
4y = x + z + 30
Now, we have an equation with three variables (x, y, and z). We need more information to solve for y.