A car drives around a curve with radius 390 m at a speed of 32 m/s. The road is not banked. The mass of the car is 1200 kg.
(a) What is the frictional force on the car?
N
c) Explain
I really don't know how to solve this could someone please help me out on this. Thank you.
If the road is not banked
the frictional force = centripetal force =
= m•v²/R = 1200•32²/390 = 3150 N
To find the frictional force on the car as it drives around the curve, we can use the concept of centripetal force. Centripetal force is the force that keeps an object moving in a circular path. In this case, the frictional force provides the centripetal force.
The centripetal force can be calculated using the following formula:
F = m * v^2 / r
where:
F is the centripetal force
m is the mass of the car (1200 kg)
v is the speed of the car (32 m/s)
r is the radius of the curve (390 m)
Let's plug in the values and solve for the frictional force:
F = (1200 kg) * (32 m/s)^2 / 390 m
Calculating the above expression, we get:
F ≈ 996.92 N
So the frictional force on the car is approximately 996.92 N.
Explanation:
To calculate the frictional force on the car, we used the formula for centripetal force and substituted the given values of mass, speed, and radius into the equation. By solving the equation, we obtained the frictional force on the car, which is the force needed to keep the car moving in a circular path without slipping.