1)A force vector points at an angle of 12.4 ° above the +x axis. It has a y component of +337 newtons (N). Find the magnitude and the x component of the force vector.
For the x component I did 337cos(12.4)=329.13 N
For magnitude I am not sure what to do.
sinα =F(y)/F => F =F(y)/ sinα,
tan α = F(y)/F(x) => F(x) =F(y)/tanα.
To find the magnitude of the force vector, you can use the Pythagorean theorem. The magnitude (or length) of a vector can be found using the formula:
Magnitude = √(x^2 + y^2)
In this case, we already know the y-component of the force vector (+337 N), which is the vertical component. To find the x-component, you correctly used the formula: x-component = 337 * cos(12.4) = 329.13 N.
Now, substitute the values into the magnitude formula:
Magnitude = √(329.13^2 + 337^2)
Calculating this expression will give you the magnitude of the force vector.