if a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then average speed is?
The time
for the first part is
t1 =2•s/5•v1,
for the second part is
t2 = 3•s/5•v2.
The total time is
t =t1+t2 =
=(2•s/5•v1)+( 3•s/5•v2)=
=(s/5) •(2/v1 + 3/v2) =
=(s/5) •{(2•v2+3•v1)/(v1•v2)},
v(ave) = distance/total time =
=s/[(s/5) •{(2•v2+3•v1)/(v1•v2)}]=
=5•(v1•v2)/(3•v1+2v2).
5v1v2/3v1+2*3/5
To find the average speed, we need to consider the total distance and the time taken to cover that distance.
Let's assume the total distance is "D" and the first fraction of the distance covered (2/5th) is represented as "d1." Similarly, the second fraction of the distance covered (3/5th) is represented as "d2."
Given that the car covers d1 with speed v1 and d2 with speed v2, we can calculate the average speed.
To find the time taken to cover d1, we can use the formula:
Time1 = Distance1 / Speed1
Time1 = d1 / v1
Similarly, to find the time taken to cover d2, we can use the formula:
Time2 = Distance2 / Speed2
Time2 = d2 / v2
The total time taken to cover the whole distance is the sum of the individual times:
Total Time = Time1 + Time2
The average speed can be calculated using the formula:
Average Speed = Total Distance / Total Time
Average Speed = D / (Time1 + Time2)
Now, plug in the values of d1, d2, v1, and v2 to calculate the average speed.