Find the area of a regular pentagon with a side of 6ft. answer nearest tenth
61.9
See the answer for a nonagon and proceed the same way:
http://www.jiskha.com/display.cgi?id=1337912555
A=1
45(5+25)a2=1
4·5·(5+2·5)·122≈247.74875in²
To find the area of a regular pentagon, you can use the formula:
Area = (0.25 * n * s^2) / tan(π/n)
Where:
- n represents the number of sides of the polygon, which in this case is 5 for a regular pentagon.
- s represents the length of each side of the pentagon.
Given that the side length is 6ft, we can substitute these values into the formula:
Area = (0.25 * 5 * 6^2) / tan(π/5)
Area = (0.25 * 5 * 36) / tan(π/5)
Now, let's calculate the value of tan(π/5) and calculate the area.
Using a calculator, we find that tan(π/5) is approximately 0.72654.
Substituting this value into the formula:
Area = (0.25 * 5 * 36) / 0.72654
Area = 45 * 36 / 0.72654
Area ≈ 201.0608 square feet
Rounding to the nearest tenth, the area of the regular pentagon is approximately 201.1 square feet.