A Block has a mass of 50.0 kilograms. the coefficient of static friction between the block and the level floor on which it rests is 0.428 A horizontal force of 618 newtons is applied to the block to the right, as shown. will the block move?

F(fr) =k•N=k•m•g = 0.428•50•9.8 ≈ 210 N.

F>F(fr) => the block will move at the acceleration
a = (F-F(fr))/m = (618 – 210)/50 = 408/50 =8.16 m/s²

To determine if the block will move, we need to compare the force being applied to the block with the maximum static friction force that can act on the block. If the applied force is greater than or equal to the maximum static friction force, the block will move.

The maximum static friction force can be calculated using the formula: f_static = μ_static * N, where μ_static is the coefficient of static friction and N is the normal force.

In this case, the coefficient of static friction is given as 0.428. The normal force is equal to the weight of the block, which can be calculated using the formula: N = m * g, where m is the mass of the block and g is the acceleration due to gravity (which is approximately 9.8 m/s²).

Let's calculate the normal force:
N = m * g
N = 50.0 kg * 9.8 m/s²
N ≈ 490 N

Now, we can calculate the maximum static friction force:
f_static = μ_static * N
f_static = 0.428 * 490 N
f_static ≈ 209.72 N

The applied force is given as 618 N. Since the applied force (618 N) is greater than the maximum static friction force (209.72 N), the block will move.