A block is pulled to the right across a alevel surface at a constant velocity of a horizontal force of 16 newtons. what is the coefficient of kinetic friction between the block and the surface?
F = 16 N
F(fr) =k•N =k•m•g .
F =F(fr)
k =F/m•g.
You have to know the mass (or weight)
The weight of the block is 84Newtons
k =F/m•g = 16/84 =0.2
To find the coefficient of kinetic friction between the block and the surface, you need to use the formula:
frictional force = coefficient of friction × normal force
First, let's analyze the problem. We are given that the block is pulled to the right at a constant velocity, which means that the applied force exactly balances the frictional force. Therefore, the magnitude of the frictional force is equal to the magnitude of the applied force.
Given:
Applied force (F_applied) = 16 N
Next, we need to find the normal force (N) acting on the block. The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, since the block is on a level surface and not accelerating, the normal force is equal in magnitude and opposite in direction to the weight of the block. Therefore:
Weight (W) = mg, where m is the mass of the block and g is the acceleration due to gravity (approximately 9.8 m/s^2)
Since no information about the mass of the block is given in the question, we cannot proceed with calculating the normal force and the coefficient of kinetic friction without that information.