A cyclist starts at rest and accelerates to a speed of 20 m/s in 5 s. what is the acceleration of the cyclist?

Well, it sounds like this cyclist was really rushing to get somewhere! To calculate the acceleration, we can use the formula:

acceleration = (final velocity - initial velocity) / time

So, in this case, the final velocity is 20 m/s, the initial velocity is 0 m/s (since the cyclist started at rest), and the time is 5 seconds.

Let's plug in the values and do some math:

acceleration = (20 m/s - 0 m/s) / 5 s
acceleration = 20 m/s / 5 s
acceleration = 4 m/s²

So, the acceleration of the cyclist is 4 meters per second squared. That's quite an impressive sprint! Just be careful not to get any speeding tickets on the bicycle highway!

To find the acceleration of the cyclist, we can use the following equation:

Acceleration (a) = (Final velocity (v) - Initial velocity (u)) / Time taken (t)

Given:
Final velocity (v) = 20 m/s
Initial velocity (u) = 0 m/s
Time taken (t) = 5 s

Substituting these values into the equation, we have:

Acceleration (a) = (20 m/s - 0 m/s) / 5 s

Simplifying the equation:

Acceleration (a) = 20 m/s / 5 s

Acceleration (a) = 4 m/s²

Therefore, the acceleration of the cyclist is 4 m/s².

To find the acceleration of the cyclist, we can use the formula:

acceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 0 m/s (since the cyclist starts at rest)
Final velocity (v) = 20 m/s
Time (t) = 5 s

Plugging these values into the formula:

acceleration = (20 m/s - 0 m/s) / 5 s
acceleration = 20 m/s / 5 s
acceleration = 4 m/s²

Therefore, the acceleration of the cyclist is 4 m/s².

a = (V-Vo)/t = (20-0) / 5 = 4m/s^2.