Suppose you have monohybrid pea plants in your garden and find that they produce round seed to wrinkled seeds in the ratio of 3:1.
If the allele are designated (R & r) respectively, what is the probable genotypes of the wrinkled seeds which were produced (F1)?
RR & Rr
RR only
RR & rr
Rr only
rr only
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Question #4
MultipleChoice
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Note to teacher:
Note from teacher:
Suppose you have monohybrid pea plants in your garden and find that they produce round seed to wrinkled seeds in the ratio of 3:1.
If the allele are designated (R & r) respectively, what is the probable Phenotype of the parents (P1)?
all round
all wrinkled
1:1 round & wrinkled
unable to determine
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Question #5
ClickAndPlace
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Note to teacher:
Note from teacher:
If the problem type is labeled “ClickAndPlace”,click the item to select it and then click the location where it belongs;otherwise, click the item and drag it into place.
Diagram the genotypes of the P1 pea plants from the previous four questions by placing the correct answer on its correct place.
Eraser
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Question #6
ClickAndPlace
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Note to teacher:
Note from teacher:
If the problem type is labeled “ClickAndPlace”,click the item to select it and then click the location where it belongs;otherwise, click the item and drag it into place.
The results of a test cross of a tall tomato plant was 100% tall. Fill in the punnett square if all the recessive alleles (genes) came from pollen during the cross test.
Eraser
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Question #7
MultipleSelect
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Note to teacher:
Note from teacher:
The female genotype of the previous problem is:
TT
Tt
tt
homozygous
heterozygous
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Question #8
ClickAndPlace
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Note to teacher:
Note from teacher:
If the problem type is labeled “ClickAndPlace”,click the item to select it and then click the location where it belongs;otherwise, click the item and drag it into place.
Complete the punnet square for the following cross-pollination.
Female: male:
Eraser
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Question #9
FillInBlank
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Note to teacher:
Note from teacher:
From the previous problem, give the genotypic and phenotypic ratios (TT x Tt) for tall and short corn.
phenotype:
genotype ratio TT: Tt
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Question #10
ClickAndPlace
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Note to teacher:
Note from teacher:
Complete the Punnett square for the following cross-pollination and give the genotypic and phenotypic ratios: for white (WW) and black (ww)
Female: x Male:
Eraser
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Question #11
TextMultipleChoice
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Note to teacher:
Note from teacher:
With the parents from the previous problem (white WW, black ww) give the phenotype and genotype ratios for this cross.
Phenotype:
genotype ratio Ww:ww
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Question #12
FillInBlank
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Note to teacher:
Note from teacher:
To determine if a particular plant is homozygous or heterozygous you would have to with a recessive to make the check.
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Question #13
FillInBlank
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Note to teacher:
Note from teacher:
A test cross is a cross between the unknown genotype and a homozygous .
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Question #14
ClickAndPlace
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Note to teacher:
Note from teacher:
Complete a Punnett square that shows a test cross for a tall pea plant( RR x rr ) by placing the correct answer in its correct place. Place the plant to be tested at the top of the Punnett Square.)
Eraser
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Question #15
TextMultipleChoice
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Note to teacher:
Note from teacher:
With the following crosses of pea plants, give the flower color of offspring and the ratio expected (red
is dominant).
Red x red (both homozygous)
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Question #16
TextMultipleChoice
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Note to teacher:
Note from teacher:
Red (heterozygous) x white (homozygous)
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Question #17
TextMultipleChoice
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Note to teacher:
Note from teacher:
Red (heterozygous) x red (homozygous)
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Question #18
TextMultipleChoice
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Note to teacher:
Note from teacher:
Red x red (both heterozygous)
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Question #19
TextMultipleChoice
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Note to teacher:
Note from teacher:
In a dihybrid cross, the F2 will have nine genotypes, but only four phenotypes because the genes cause the traits to mask the traits.
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Question #20
FillInBlank
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Note to teacher:
Note from teacher:
A cross between plants which differ in only two traits is a cross.
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Question #21
FillInBlank
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Note to teacher:
Note from teacher:
A student analyzed ears of corn that demonstrated two traits in the F2 kernels, purple and white colors and smooth and wrinkled shape. A tabulation of 135 individual kernels gave the following results:
(purple smooth = 75, white smooth = 28, purple wrinkled = 24, white wrinkled = 8)
How many phenotypes are present?
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Question #22
Unordered
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Note to teacher:
Note from teacher:
A student analyzed ears of corn that demonstrated two traits in the F2 kernels, purple and white colors and smooth and wrinkled shape. A tabulation of 135 individual kernels gave the following results:
(purple smooth = 75, white smooth = 28, purple wrinkled = 24, white wrinkled = 8)
What are the phenotypes present?
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Question #23
TextMultipleChoice
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Note to teacher:
Note from teacher:
(purple smooth = 75, white smooth = 28, purple wrinkled = 24, white wrinkled = 8)
Which alleles are dominant?
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Question #24
TextMultipleChoice
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Note to teacher:
Note from teacher:
(purple smooth = 75, white smooth = 28, purple wrinkled = 24, white wrinkled = 8)
Which alleles are recessive?
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Question #25
ClickAndPlace
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Note to teacher:
Note from teacher:
(purple smooth (PR)= 75, white smooth (pR)= 28, purple wrinkled (Pr)= 24, white wrinkled (pr)= 8)
Using symbols, diagram a cross that would give these results by completing the punnet square by placing the correct answers in their appropriate spot.
Eraser
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Question #26
FillInBlank
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Note to teacher:
Note from teacher:
(purple smooth = 75, white smooth = 28, purple wrinkled = 24, white wrinkled = 8)
According to the Punnett square you completed in the previous question, the predicted results should have been 9/16 purple smooth (56.3%), 3/16 purple wrinkled (18.8%), 3/16 white smooth (18.8%), and 1/16 white wrinkled (6.3%).
Do the corn kernels compare in number exactly to the predicted number?
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Question #27
Paragraph
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Note to teacher:
Note from teacher:
(purple smooth = 75, white smooth = 28, purple wrinkled = 24, white wrinkled = 8)
Account for the difference between the expected and experimental values.
Save
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Question #28
FillInBlank
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Note to teacher:
Note from teacher:
One of Mendel's main principles of inheritance, the principle of is illustrated with the previous activities.
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Question #29
TrueFalse
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Note to teacher:
Note from teacher:
All the gene pairs from one parent can congregate in one gamete and those from the other parent in other gamete.
True
False
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Question #30
FillInBlank
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Note to teacher:
Note from teacher:
The phenotypic ratio for the F2 generation in a dihybrid cross will theoretically be .
If you use a Punnett square <(Broken Link Removed) you will be able to test the genotype probabilities. Assuming R indicates a dominant gene and r indicates a recessive, whenever you have an R in the genotype, you will have a round seed. Only rr wil result in wrinkled seeds.
I hope this helps. Thanks for asking.
Question #4: The probable genotypes of the wrinkled seeds (F1) are Rr only.
Question #5: The probable phenotype of the parents (P1) is all round.
Question #6: To diagram the genotypes of the P1 pea plants, we need more information.
Question #7: The female genotype of the previous problem can be either TT or Tt, depending on the parental genotypes.
Question #8: To complete the punnet square for the cross-pollination, we need the genotypes of the female and male parents.
Question #9: To determine the genotypic and phenotypic ratios for tall and short corn, we need the genotypes of the parents.
Question #10: To complete the Punnett square for the cross-pollination, we need the genotypes of the female and male parents.
Question #11: With the parents being white (WW) and black (ww), the phenotype ratio for this cross will depend on the parental genotypes.
Question #12: To determine if a particular plant is homozygous or heterozygous, you would have to perform a test cross with a recessive genotype.
Question #13: A test cross is a cross between the unknown genotype and a homozygous recessive individual.
Question #14: To complete the Punnett square for the test cross, we need the genotype of the plant to be tested.
Question #15: The flower color of offspring and the ratio expected in the cross between red homozygous parents is not provided.
Question #16: The flower color of offspring and the ratio expected in the cross between a red heterozygous parent and a white homozygous parent is not provided.
Question #17: The flower color of offspring and the ratio expected in the cross between a red heterozygous parent and a red homozygous parent is not provided.
Question #18: The flower color of offspring and the ratio expected in the cross between red heterozygous parents is not provided.
Question #19: In a dihybrid cross, the F2 generation will have sixteen genotypes, not just nine.
Question #20: A cross between plants that differ in only two traits is a dihybrid cross.
Question #21: The number of phenotypes present from the tabulation of 135 individual kernels is not provided.
Question #22: The phenotypes present from the tabulation of 135 individual kernels are not provided.
Question #23: The dominant alleles from the tabulation are not provided.
Question #24: The recessive alleles from the tabulation are not provided.
Question #25: To diagram a cross that would give the specific results, we need the symbols used for the alleles and the parental genotypes.
Question #26: Without the specific genotypes and parental genotypes, we cannot determine if the corn kernels compare exactly to the predicted number.
Question #27: The difference between the expected and experimental values cannot be determined without the specific genotypes and parental genotypes.
Question #28: One of Mendel's main principles of inheritance, the principle of segregation, may be illustrated with the previous activities.
Question #29: False. All the gene pairs from one parent can segregate randomly into different gametes.
Question #30: The phenotypic ratio for the F2 generation in a dihybrid cross will theoretically be 9:3:3:1.
Question #4: The probable genotypes of the wrinkled seeds (F1) can be determined by looking at the phenotypic ratio of round seed to wrinkled seeds, which is 3:1. This indicates that the round seed phenotype is dominant, and the wrinkled seed phenotype is recessive. Since the allele for round seed is designated as "R" and the allele for wrinkled seed is designated as "r", the probable genotypes for the wrinkled seeds are rr only.
To determine the genotypes, one needs to understand the Mendelian genetics principles and the concept of dominant and recessive alleles. In this case, knowing the phenotypic ratio and the allele designations allows us to infer the genotypes of the offspring.
Question #5: The probable phenotype of the parents (P1) can be determined by observing the phenotypic ratio of round seed to wrinkled seeds, which is 3:1. If all the offspring have round seeds, it indicates that the parents have the genotype for round seeds. Therefore, the probable phenotype of the parents is all round.
Observing the phenotype of the offspring allows us to determine the probable phenotype of the parents. This is because the phenotype is determined by the expression of the genes (alleles) in an individual.
Note: In cases where the phenotypic ratio is not provided, it would be challenging to determine the probable phenotype of the parents without additional information.
Question #7: The female genotype of the previous problem can be determined by considering the possible genotypes based on the given information. In this case, we know that the parents produced round and wrinkled seeds in a ratio of 3:1, which indicates that one parent must have a dominant (round seed) allele and the other parent must have a recessive (wrinkled seed) allele. Therefore, the female genotype can be either homozygous (RR) or heterozygous (Rr).
To determine the female genotype, one needs to consider the possible combinations of alleles based on the observed phenotypic ratio. In this case, the female could have either two dominant alleles (homozygous) or one dominant and one recessive allele (heterozygous).
Note: The male genotype is not provided, so we cannot determine its genotype without additional information.
Question #9: To determine the genotypic and phenotypic ratios of the tall and short corn from the previous problem (TT x Tt), one needs to understand the principles of Mendelian genetics and the concept of dominant and recessive alleles.
In this case, the genotype for tall corn is TT, and the genotype for short corn is Tt. The phenotypes are determined by the expression of these genotypes, where the dominant allele (T) results in the tall phenotype and the recessive allele (t) results in the short phenotype.
Therefore, the genotypic ratio for tall and short corn is TT:Tt, and the phenotypic ratio is 1:1.
Note: The ratios may vary depending on the specific cross and the inheritance pattern of the traits involved.
Question #11: With the parents from the previous problem (white WW, black ww), the phenotype and genotype ratios can be determined by understanding the principles of Mendelian genetics and the concept of dominant and recessive alleles.
In this case, the cross is between a white (homozygous recessive) parent and a black (homozygous dominant) parent. The offspring will inherit one allele from each parent, resulting in the following possibilities:
- Ww: This genotype represents individuals with one dominant allele and one recessive allele. The phenotype will be black.
- ww: This genotype represents individuals with two recessive alleles. The phenotype will be white.
Therefore, the phenotype ratio is black: white, and the genotype ratio is Ww: ww.
Note: The specific traits and their alleles are not provided in this question, so we have assumed that white is recessive and black is dominant based on common genetic conventions. The actual alleles and their dominance relationship may vary depending on the specific traits being considered.