Log to the base of 3 (x-4)=2
To solve the equation log base 3 of (x-4) = 2, we need to eliminate the logarithm by rewriting it in exponential form.
The logarithm equation log base a of b = c can be rewritten as a^c = b.
In our case, we have log base 3 of (x-4) = 2. Rewriting this in exponential form, we have 3^2 = (x-4).
Simplifying 3^2, we get 9. Therefore, the equation becomes 9 = (x-4).
To solve for x, we need to isolate it. Adding 4 to both sides of the equation, we get 9 + 4 = x, which can be further simplified as x = 13.
Therefore, the solution to the equation log base 3 of (x-4) = 2 is x = 13.