C25H52 + __38__ O2 -------> __25__ CO2 + __26__ H2O + energy
a) Balance the equation. Count atoms below.
___________ carbon ___________
___________hydrogen___________
____________oxygen____________
C25H52 + 38O2 -------> 25CO2 + 26H2O + energy
You've done the hard part. The easy part is counting them.
25 .....C........25
52......H........50
76......O.........76
To balance the equation, we need to ensure that the number of atoms on each side of the equation is equal. Here's how we can count the atoms to balance the equation:
On the left side of the equation:
Carbon (C): 25 atoms (from C25H52)
Hydrogen (H): 52 atoms (from C25H52)
Oxygen (O): 2 atoms (from O2)
On the right side of the equation:
Carbon (C): 25 atoms (from 25 CO2)
Hydrogen (H): 26 atoms (from 26 H2O)
Oxygen (O): 64 atoms (from 38 O2 and 26 H2O)
To balance the number of atoms, we need to adjust the coefficients (numbers in front of the formulas) of the compounds. We can start by balancing carbon:
We have 25 carbon atoms on both sides, so carbon is already balanced.
Next, we balance hydrogen:
On the left side, we have 52 hydrogen atoms, and on the right side, we have 26 hydrogen atoms from water (2 per water molecule). To balance hydrogen, we need 26 more hydrogen atoms. We can achieve this by placing a coefficient of 13 in front of H2O.
The equation now looks like this:
C25H52 + 38 O2 → 25 CO2 + 13 H2O + energy
Finally, we balance oxygen:
On the left side, we have 2 oxygen atoms from O2, and on the right side, we have 25×2=50 oxygen atoms from CO2 and 13×1=13 oxygen atoms from H2O, which gives us a total of 50+13=63 oxygen atoms. To balance oxygen, we need to add 38 more oxygen atoms. We can do this by placing a coefficient of 19 in front of O2.
The final balanced equation is:
C25H52 + 38 O2 → 25 CO2 + 13 H2O + energy.
After balancing the equation, we have:
Carbon (C): 25 atoms on both sides
Hydrogen (H): 52 atoms on both sides
Oxygen (O): 76 atoms on both sides.
To balance the equation:
C25H52 + 38O2 → 25CO2 + 26H2O + energy
We start by counting the number of atoms on each side of the equation:
Carbon (C):
Left side: 25
Right side: 25
Hydrogen (H):
Left side: 52
Right side: 52
Oxygen (O):
Left side: 2 (from O2)
Right side: 2 (from CO2) + 26 (from H2O) = 28
Now, we need to balance the number of oxygen atoms. Since there are 28 oxygen atoms on the right side and only 2 on the left side, we need to add 26 O2 molecules on the left side to balance the equation:
C25H52 + 38O2 → 25CO2 + 26H2O + energy