The sum of the ages of Travis, Mac and Ellie is 44. Travis is 4 years older than Ellie and Mac is twice as old as Ellie. How old is each?
let x = age of Travis
let x-4 = age of Ellie (since Travis is four years older than Ellie)
let 2(x-4) = age of Mac (since he is twice older than Ellie)
since the sum of their ages is 44,
x + x - 4 + 2(x - 4) = 44
2x - 4 + 2x - 8 = 44
4x - 12 = 44
4x = 56
x = 14 yrs old (Travis)
x-4 = 10 yrs old (Ellie)
2(x-4) = 20 yrs old (Mac)
hope this helps~ :)
A CIRCULAR PIECE OF CARDBOARD IS TRIMMEM IN SUCH A WAY THAT ITS CIRCUMFERENCE IS REDUCED IN THE RATIO 3:7. IN WHAT RATIO IS THE SURFACE AREA REDUCED?
To solve this problem, we can use a system of equations.
Let's assign some variables to the ages of Travis, Mac, and Ellie. Let E represent Ellie's age.
From the given information, we can determine:
Travis = E + 4 (Travis is 4 years older than Ellie)
Mac = 2E (Mac is twice as old as Ellie)
The sum of their ages is given as 44:
Travis + Mac + Ellie = 44
(E + 4) + (2E) + E = 44
4E + 4 = 44
4E = 40
E = 10
Ellie is 10 years old. To find the ages of Travis and Mac, we substitute the value of E back into the equations we formed earlier:
Travis = E + 4 = 10 + 4 = 14
Mac = 2E = 2 * 10 = 20
Therefore, Travis is 14 years old, Mac is 20 years old, and Ellie is 10 years old.