Evaluate the following expressions for x=-3
13)–2x^2 =
14)(-2x)^2 =
10)Use the discriminant to determine
the number of solutions of 3x^2-4x+6=0
8)Solve sqrt[3b] = -3
13. -2*(-3)^2 = -18.
14. (-2x)^2 = (-2*(-3)^2 = 6^2 = 36.
10. 3x^2 - 4x + 6 = 0.
D = sqrt(B^2-4AC).
D = sqrt(16-72) = sqrt(-56).
The Discriminant is < 0; therefore, we
have no real solutions and 2 imaginary
solutions.
8. sqrt(3b) = -3
Square both sides:
3b = 9
b = 3,
CHECK: sqrt(3*3) = sqrt(9)=+3,AND -3.