A car drives straight off the edge of a cliff that is 68 m high. The police at the scene of the accident note that the point of impact is 148 m from the base of the cliff. How fast was the car traveling when it went over the cliff?
H =g•t²/2 => t =sqrt(2•H/g) = sqrt(2•68/9.8) =3.7 s.
L = v•t => v =L/t = 148/3.7= 39.7 m/s = 143 km/hr =88.8mph
posted by Elena