A drawer contains 4 red socks, 3 white socks, and 3 blue socks. without looking, you select a sock at random, replace it and seect a sond sock at random. what is the probablity that the first sock is blue and the second sock is red?
You shouldn't be helping people
With replacement:
P(B,R)=P(B)*P(R)=(3/10)*(4/10)=12/100=3/25
3/10
4/9
"...replace it and seect a second sock at random..."
To find the probability that the first sock is blue and the second sock is red, we can use the concept of probability.
Step 1: Calculate the probability of selecting a blue sock on the first draw.
There are a total of 4 red socks + 3 white socks + 3 blue socks = 10 socks in the drawer.
The probability of choosing a blue sock on the first draw is 3 blue socks / 10 total socks = 3/10.
Step 2: Calculate the probability of selecting a red sock on the second draw.
Since we replaced the first sock after selecting it, the total number of socks in the drawer does not change. Therefore, there are still 10 socks in the drawer.
The probability of choosing a red sock on the second draw is 4 red socks / 10 total socks = 4/10.
Step 3: Multiply the probabilities from steps 1 and 2.
To find the probability of both events occurring (the first sock is blue and the second sock is red), we multiply the probabilities together:
Probability = (3/10) * (4/10) = 12/100 = 0.12
So, the probability that the first sock is blue and the second sock is red is 0.12 or 12%.