A car of mass 1670 kg is traveling without slipping on a flat, curved road with a radius of curvature of 34 m. If the car's speed is 14 m/s, what is the frictional force between the road and the tires?
It is the centripetal force, M V^2/R.
I get 8610 Newtons
F(fr) = m•a = m•v²/R =
=1670•(14)²/34 =9627 N
To find the frictional force between the road and the car's tires, we can use the centripetal force equation. The centripetal force is provided by the frictional force in this case.
The centripetal force is given by:
F = (m * v^2) / r
Where:
F is the centripetal force
m is the mass of the car (1670 kg)
v is the velocity of the car (14 m/s)
r is the radius of curvature (34 m)
Now, we can substitute the given values into the equation:
F = (1670 kg * (14 m/s)^2) / 34 m
Calculating the centripetal force:
F = (1670 kg * 196 m^2/s^2) / 34 m
F = 964840 kg•m/s^2 / 34 m
F ≈ 28407.06 N
Therefore, the frictional force between the road and the tires is approximately 28407.06 Newtons.