How many mls of .1M KOH would it take to neutralize 75 mls of .07M CH3COOH?
mols CH3COOH = M x L = ?
mols KOH = same since the reaction is 1 mol CH3COOH + KOH ==> CH3COOK + H2O.
Then M KOH = mols/L. You know mols and M, solve for L and convert to mL.