a bullet initially moving with a velocity 20m/s strikes a target and comes to rest after penetrating a distance 10cm in the target calculate the retardation/deceleration caused by the target.
Vf^2=Vi^2+2ad
solve for a.
can u do it fully
PLEASE
0 = v –a•t, t = v/a,
s = v•t - at²/2 = v²/a – (a/2)• (v/a)² = v²/2•a.
a = v²/2•s = 20²/2•0.1 =2000 m/s²
Who the hell are you riana ?
To calculate the retardation or deceleration caused by the target, we can use the equation of motion:
v^2 = u^2 + 2as
Where:
v = final velocity (which is zero since the bullet comes to rest)
u = initial velocity (20 m/s)
a = acceleration (retardation in this case)
s = distance traveled (10 cm = 0.1 m)
Rearranging the equation, we get:
a = (v^2 - u^2) / (2s)
Substituting the known values:
a = (0 - (20^2)) / (2 * 0.1)
Simplifying the equation:
a = (-400) / 0.2
a = -2000 m/s^2
Therefore, the retardation or deceleration caused by the target is -2000 m/s^2. The negative sign indicates that the acceleration is in the opposite direction to the initial velocity.