a car starts from rest , attains a velocity of 36kmph with an acceleration of 0.2m/s^2 travels 9km with this uniform velocity and then comes to halt with a uniform acceleration of 0.1m/s^2 find the total time of travel of the car.

v = 36 km/hr =36000/3600 = 10 m/s.

1. v =a1•t1, t1= v/a = 10/0.2 = 50 s.
2. t2 = s/v = 9000/10 = 900 s.
3. 0 = v-a•t3,
t3 = v/a2 = 10/0.1 = 100 s.
t(total) = 50+900+100 = 1050 s = 17.5 min.

What is in the 2 nd step...im not getting it.

An automobile starts from rest and attains a velocity of 36km/hr in 30 minute .what is the acceleration in m/s2?

Seience slop

To find the total time of travel of the car, we need to calculate the time it takes for the car to accelerate to 36 km/h, the time it takes to travel 9 km with uniform velocity, and the time it takes to decelerate and come to a halt.

Let's break down the problem step by step:

Step 1: Finding the time to reach a velocity of 36 km/h

We know that the acceleration of the car is 0.2 m/s^2 and the initial velocity is 0 (rest). We need to convert the final velocity from km/h to m/s:

Final velocity = 36 km/h = 36 * (1000/3600) m/s = 10 m/s

We can use the following equation to calculate the time it takes to reach the final velocity:

Final velocity = Initial velocity + (Acceleration * Time)

Rearranging the equation:

Time = (Final velocity - Initial velocity) / Acceleration

Time = (10 - 0) / 0.2 = 50 seconds

So, it takes 50 seconds for the car to reach a velocity of 36 km/h.

Step 2: Finding the time to travel 9 km with uniform velocity

Since the car travels at a uniform velocity of 36 km/h, we can calculate the time it takes using the formula:

Time = Distance / Velocity

Distance = 9 km = 9 * 1000 m = 9000 m

Velocity = 36 km/h = 36 * (1000/3600) m/s = 10 m/s

Time = 9000 m / 10 m/s = 900 seconds

So, it takes 900 seconds to travel 9 km with uniform velocity.

Step 3: Finding the time to come to a halt with uniform deceleration

We know that the acceleration while coming to a halt is -0.1 m/s^2 (negative since it's deceleration). We need to calculate the time using the same equation as step 1:

Time = (Final velocity - Initial velocity) / Acceleration

Final velocity = 0 (comes to a halt)

Acceleration = -0.1 m/s^2

Initial velocity = 10 m/s (the uniform velocity from step 2)

Time = (0 - 10) / (-0.1) = 100 seconds

So, it takes 100 seconds for the car to come to a halt.

Step 4: Finding the total time of travel

The total time of travel is the sum of the times from step 1, step 2, and step 3:

Total time = Time to reach a velocity of 36 km/h + Time to travel 9 km with uniform velocity + Time to come to a halt

Total time = 50 seconds + 900 seconds + 100 seconds = 1050 seconds

Therefore, the total time of travel for the car is 1050 seconds.

I can understand it . It is very helpful for my studies