The equation that describes the path of a small rocket after it is shot into the air is h=1120-16t^2, where h is the height above the ground, in feet, after t seconds. How many seconds does it take for the rocket to return to the ground?
I don't believe that equation. Recheck it.
To find the time it takes for the rocket to return to the ground, we need to determine when the height (h) is equal to 0.
In the equation h = 1120 - 16t^2, we substitute h with 0 and solve for t:
0 = 1120 - 16t^2
To make the equation easier to solve, we can rearrange it as follows:
16t^2 = 1120
Now, divide both sides of the equation by 16:
t^2 = 70
To isolate t, take the square root of both sides:
t = √70
Therefore, the rocket takes approximately (√70) seconds to return to the ground.