If a family has 4 children, in how many ways could the parents have 2 boys and 2 girls as children?
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4!/2!2!=4*3*2*1/2*2=6
Write 5*10^ -4 in decimal notation.
Select the correct answer.
0.00005
-50000
-5000
0.0005
0.0005
To determine the number of ways the parents can have 2 boys and 2 girls as children, we can use the concept of permutations.
First, we need to determine the number of ways in which the 2 boys can be born. Since there are 4 children in total and 2 of them are boys, we have to choose 2 boys out of 4. This can be calculated using the combination formula:
C(4, 2) = 4! / (2! * (4 - 2)!)
C(4, 2) = 4! / (2! * 2!)
C(4, 2) = 6
So there are 6 different ways for the parents to have 2 boys.
Next, we need to determine the number of ways in which the 2 girls can be born. Similarly, since there are 4 children in total and 2 of them are girls, we have to choose 2 girls out of 4.
C(4, 2) = 4! / (2! * (4 - 2)!)
C(4, 2) = 4! / (2! * 2!)
C(4, 2) = 6
So there are also 6 different ways for the parents to have 2 girls.
To find the total number of possible outcomes, we multiply the number of ways to have 2 boys by the number of ways to have 2 girls:
Total number of ways = Number of ways to have 2 boys * Number of ways to have 2 girls
Total number of ways = 6 * 6
Total number of ways = 36
Therefore, there are 36 different ways for the parents to have 2 boys and 2 girls as children.