If a family has 4 children, in how many ways could the parents have 2 boys and 2 girls as children?

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4!/2!2!=4*3*2*1/2*2=6

Write 5*10^ -4 in decimal notation.

Select the correct answer.
0.00005
-50000
-5000
0.0005

0.0005

To determine the number of ways the parents can have 2 boys and 2 girls as children, we can use the concept of permutations.

First, we need to determine the number of ways in which the 2 boys can be born. Since there are 4 children in total and 2 of them are boys, we have to choose 2 boys out of 4. This can be calculated using the combination formula:

C(4, 2) = 4! / (2! * (4 - 2)!)

C(4, 2) = 4! / (2! * 2!)

C(4, 2) = 6

So there are 6 different ways for the parents to have 2 boys.

Next, we need to determine the number of ways in which the 2 girls can be born. Similarly, since there are 4 children in total and 2 of them are girls, we have to choose 2 girls out of 4.

C(4, 2) = 4! / (2! * (4 - 2)!)

C(4, 2) = 4! / (2! * 2!)

C(4, 2) = 6

So there are also 6 different ways for the parents to have 2 girls.

To find the total number of possible outcomes, we multiply the number of ways to have 2 boys by the number of ways to have 2 girls:

Total number of ways = Number of ways to have 2 boys * Number of ways to have 2 girls

Total number of ways = 6 * 6

Total number of ways = 36

Therefore, there are 36 different ways for the parents to have 2 boys and 2 girls as children.