1.)A radio station transmits waves of length 400m.if the speed of the waves is 3*10power8m/sec,find the frequency of the radio station.
2.)Audible range of frequencies is between 20Hz and 20KHz.Find the range of the wavelengths corresponding to these frequencies.given,velocity of sound=300m/sec
1.) To find the frequency of the radio station, we can use the formula:
Frequency (f) = Speed of Waves (v) ÷ Wavelength (λ)
Given:
Speed of Waves (v) = 3 x 10^8 m/s
Wavelength (λ) = 400 m
We can substitute these values into the formula to find the frequency:
f = (3 x 10^8 m/s) ÷ (400 m)
f = 7.5 x 10^5 Hz
Therefore, the frequency of the radio station is 7.5 x 10^5 Hz.
2.) To find the range of wavelengths corresponding to the audible frequencies of 20 Hz to 20 kHz, we can use the formula:
Wavelength (λ) = Speed of Sound (v) ÷ Frequency (f)
Given:
Speed of Sound (v) = 300 m/s
Lowest Frequency (f1) = 20 Hz
Highest Frequency (f2) = 20,000 Hz
We can find the wavelength for both frequencies:
For the lowest frequency (f1 = 20 Hz):
λ1 = (300 m/s) ÷ (20 Hz)
λ1 = 15 m
For the highest frequency (f2 = 20,000 Hz):
λ2 = (300 m/s) ÷ (20,000 Hz)
λ2 = 0.015 m
Therefore, the range of wavelengths corresponding to the audible frequencies is from 15 meters (λ1) to 0.015 meters (λ2).
Use the appropriate formulas.
1. f = (wave speed)/(wavelength)
= 3*10^8/400 = ___ Hz
2. Longer audible wavelength
= (300 m/s)/(lower frequency)
= ___ m
Shorter audible wavelength
= (300 m/s)/(maximum frequency)
= ___ m