calculate grams of potassium bromide dissolved in 50 grams of water at 0 celcius
To calculate the grams of potassium bromide dissolved in 50 grams of water at 0 degrees Celsius, we need to know the solubility of potassium bromide at that temperature.
The solubility of a substance in a solvent is typically given in units of grams per 100 grams of solvent (g/100g). In this case, we'll need to find the solubility of potassium bromide in water at 0 degrees Celsius.
To do this, we can refer to a solubility chart or table. Typically, these charts provide solubility values for different substances at different temperatures.
Once we have the solubility value, we can calculate the grams of potassium bromide dissolved by using the given mass of water.
Let's assume that the solubility of potassium bromide at 0 degrees Celsius is 70 g/100g of water.
To find the grams of potassium bromide dissolved in 50 grams of water, we can set up a proportion:
(70 g KBr / 100 g water) = (x g KBr / 50 g water)
Cross-multiplying, we get:
70 g KBr * 50 g water = 100 g water * x g KBr
Simplifying, we find:
3500 g KBr = 100 g water * x g KBr
Dividing both sides by 100 g water, we get:
35 g KBr = x g KBr
Therefore, at 0 degrees Celsius, 50 grams of water can dissolve 35 grams of potassium bromide.