If Sally places a rocket that is 3 feet 6 inches tall atop a launch pad that is 1 foot 8 inches tall, how tall will the entire unit, rocket and launch pad, be when she is done?


A.5 feet 4 inches
B.5 feet 2 inches
C.1 foot 8 inches
D.4 feet 2 inches
B?
3 feet 6 inches converts as:
3 feet x 12 inches/foot = 36 inches.
36 inches + 6 inches = 42 inches.
1 foot 8 inches converts to:
1 foot x 12 inches/foot = 12 inches.
12 inches + 8 inches = 20 inches.
Then

42 + 20 = 62 inches.

62 divided by 12 = 5 remainder 2,

which is 5 feet 2 inches.
Is this correct?

yes, and yes.

Yes, your calculation is correct. The entire unit, including the rocket and the launch pad, will be 5 feet 2 inches tall.

To explain how you arrived at this answer:
First, you converted the height of the rocket, which is 3 feet 6 inches, into inches. You multiplied the number of feet (3) by 12, since there are 12 inches in a foot, and then added the remaining inches (6). This resulted in a total height of 42 inches for the rocket.

Next, you converted the height of the launch pad, which is 1 foot 8 inches, into inches as well. Again, you multiplied the number of feet (1) by 12 and added the remaining inches (8), which gave you a total height of 20 inches for the launch pad.

Finally, you added the heights of the rocket and the launch pad to get the total height of the entire unit. 42 inches + 20 inches equals 62 inches.

Since there are 12 inches in a foot, you divided the total height of 62 inches by 12 and found that it is equivalent to 5 feet with a remainder of 2 inches. Therefore, the correct answer is B. 5 feet 2 inches.